x^{8} - 9y^{4} = (x^{2} – ay)(x^{4} + cy^{2})(bx^{2} + √3y), then find the value of a^{2} + b – c.

- 0
- 1
- 2
- 4

Option 2 : 1

**Given :**

x^{8} - 9y^{4} = (x^{2} – ay)(x^{4} + cy^{2})(bx^{2} + √3y)

**Formula used :**

a^{2} – b^{2 }= (a + b) (a – b)

**Calculations :**

x^{8} – 9y^{4} = (x^{4} – 3y^{2})(x^{4} + 3y^{2})

⇒ (x^{2} - √3y)(x^{2} + √3y)(x^{4} + 3y^{2})

(x^{2} - √3y)(x^{2} + √3y)(x^{4} + 3y^{2}) = (x^{2} – ay)(x^{4} + cy^{2})(bx^{2} + √3y)

So, we will get a = √3, b =1 and c = 3.

a^{2} + b – c = 3 + 1 – 3

⇒ 1

**∴ Option 2 will be the correct answer. **

India’s **#1 Learning** Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Trusted by 2,18,23,822+ Students

Testbook Edu Solutions Pvt. Ltd.

1st & 2nd Floor, Zion Building,

Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

[email protected]
Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

Toll Free:1800 833 0800

Office Hours: 10 AM to 7 PM (all 7 days)